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laurent
46a84a64d6
for the regex now the functions name is :
func captureGroups(from regexPattern: String) -> [String]? {
and fixing some spaces and one typo.
I am sorry, I am quite new to this. Hope I did not change too much at once. Thank you
64 lines
1.5 KiB
Swift
64 lines
1.5 KiB
Swift
//
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// Comparable.swift
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// Terminal
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//
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// Created by Paul Hudson on 20/02/2020.
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// Copyright © 2020 Hacking with Swift. All rights reserved.
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//
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import Foundation
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func +<I: BinaryInteger, F: BinaryFloatingPoint>(lhs: I, rhs: F) -> F {
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return F(lhs) + rhs
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}
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func +<I: BinaryInteger, F: BinaryFloatingPoint>(lhs: F, rhs: I) -> F {
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return lhs + F(rhs)
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}
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func -<I: BinaryInteger, F: BinaryFloatingPoint>(lhs: I, rhs: F) -> F {
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return F(lhs) - rhs
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}
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func -<I: BinaryInteger, F: BinaryFloatingPoint>(lhs: F, rhs: I) -> F {
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return lhs - F(rhs)
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}
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func *<I: BinaryInteger, F: BinaryFloatingPoint>(lhs: I, rhs: F) -> F {
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return F(lhs) * rhs
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}
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func *<I: BinaryInteger, F: BinaryFloatingPoint>(lhs: F, rhs: I) -> F {
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return lhs * F(rhs)
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}
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func /<I: BinaryInteger, F: BinaryFloatingPoint>(lhs: I, rhs: F) -> F {
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return F(lhs) / rhs
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}
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func /<I: BinaryInteger, F: BinaryFloatingPoint>(lhs: F, rhs: I) -> F {
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return lhs / F(rhs)
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}
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// ------------------------------------------
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// How to replicate the ** operator in Swift
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//
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infix operator **
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func **<I: BinaryInteger>(lhs: I, rhs: I) -> I {
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return I(pow(Double(lhs), Double(rhs)))
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}
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func **<I: BinaryInteger, F: BinaryFloatingPoint>(lhs: I, rhs: F) -> F {
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return F(pow(Double(lhs), Double(rhs)))
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}
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func **<I: BinaryInteger, F: BinaryFloatingPoint>(lhs: F, rhs: I) -> F {
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return F(pow(Double(lhs), Double(rhs)))
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}
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func **<F: BinaryFloatingPoint>(lhs: F, rhs: F) -> F {
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return F(pow(Double(lhs), Double(rhs)))
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}
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