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Now, as the page_ext holds count of IOMMU mappings, we can use it to assert that any page allocated/freed is indeed not in the IOMMU. The sanitizer doesn’t protect against mapping/unmapping during this period. However, that’s less harmful as the page is not used by the kernel. Reviewed-by: Samiullah Khawaja <skhawaja@google.com> Reviewed-by: Lu Baolu <baolu.lu@linux.intel.com> Signed-off-by: Mostafa Saleh <smostafa@google.com> Reviewed-by: Pranjal Shrivastava <praan@google.com> Signed-off-by: Joerg Roedel <joerg.roedel@amd.com>
33 lines
860 B
C
33 lines
860 B
C
// SPDX-License-Identifier: GPL-2.0-only
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/*
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* Copyright (C) 2025 - Google Inc
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* Author: Mostafa Saleh <smostafa@google.com>
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* IOMMU API debug page alloc sanitizer
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*/
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#ifndef __LINUX_IOMMU_DEBUG_PAGEALLOC_H
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#define __LINUX_IOMMU_DEBUG_PAGEALLOC_H
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#ifdef CONFIG_IOMMU_DEBUG_PAGEALLOC
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DECLARE_STATIC_KEY_FALSE(iommu_debug_initialized);
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extern struct page_ext_operations page_iommu_debug_ops;
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void __iommu_debug_check_unmapped(const struct page *page, int numpages);
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static inline void iommu_debug_check_unmapped(const struct page *page, int numpages)
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{
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if (static_branch_unlikely(&iommu_debug_initialized))
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__iommu_debug_check_unmapped(page, numpages);
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}
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#else
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static inline void iommu_debug_check_unmapped(const struct page *page,
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int numpages)
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{
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}
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#endif /* CONFIG_IOMMU_DEBUG_PAGEALLOC */
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#endif /* __LINUX_IOMMU_DEBUG_PAGEALLOC_H */
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