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0ac329ec01
* Also enhanced reporting error exit reporting through the scons logger to provide the exception in the compilation report. * More error exits in scons should do this.
123 lines
2.9 KiB
Python
123 lines
2.9 KiB
Python
# Copyright 2025, Kay Hayen, mailto:kay.hayen@gmail.com find license text at end of file
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"""Cover list contractions and a few special things in them."""
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from __future__ import print_function
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# Tests do bad things, pylint: disable=possibly-unused-variable,redefined-outer-name
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def displayDict(d):
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result = "{"
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first = True
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for key, value in sorted(d.items()):
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if not first:
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result += ","
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result += "%s: %s" % (repr(key), repr(value))
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first = False
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result += "}"
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return result
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print("List contraction on the module level:")
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x = [(u if u % 2 == 0 else 0) for u in range(10)]
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print(x)
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print("List contraction on the function level:")
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def someFunction():
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x = [(u if u % 2 == 0 else 0) for u in range(10)]
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print(x)
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someFunction()
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print("List contractions with no, 1 one 2 conditions:")
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def otherFunction():
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print([x for x in range(8)])
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print([x for x in range(8) if x % 2 == 1])
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print([x for x in range(8) if x % 2 == 1 if x > 4])
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otherFunction()
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print("Complex list contractions with more than one for:")
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def complexContractions():
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print([(x, y) for x in range(3) for y in range(5)])
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seq = range(3)
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res = [(i, j, k) for i in iter(seq) for j in iter(seq) for k in iter(seq)]
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print(res)
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complexContractions()
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print("Contraction for 2 for statements and one final if referring to first for:")
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def trickyContraction():
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class Range:
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def __init__(self, value):
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self.value = value
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def __iter__(self):
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print("Giving range iter to", self.value)
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return iter(range(self.value))
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def Cond(y):
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print("Checking against", y)
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return y == 1
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r = [(x, z, y) for x in Range(3) for z in Range(2) for y in Range(4) if Cond(y)]
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print("result is", r)
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trickyContraction()
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def lambdaWithcontraction(x):
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l = lambda x: [z for z in range(x)]
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r = l(x)
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print("Lambda contraction locals:", displayDict(locals()))
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lambdaWithcontraction(3)
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print("Contraction that gets a 'del' on the iterator variable:", end=" ")
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def allowedDelOnIteratorVariable(z):
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x = 2
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del x
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return [x * z for x in range(z)]
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print(allowedDelOnIteratorVariable(3))
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# Python tests originally created or extracted from other peoples work. The
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# parts were too small to be protected.
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#
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# Licensed under the Apache License, Version 2.0 (the "License");
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# you may not use this file except in compliance with the License.
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# You may obtain a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS,
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# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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# See the License for the specific language governing permissions and
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# limitations under the License.
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