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[Sema] Fully allow fallthrough in switch expressions

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Allow `fallthrough` to appear as the last statement
in the case of a `switch` expression. We already
allowed it in other positions, this was just an
oversight.

rdar://127670432
This commit is contained in:
Hamish Knight
2024-08-14 19:59:05 +01:00
parent 55aed16ee6
commit 769805e714
6 changed files with 137 additions and 29 deletions
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54
test/stmt/then_stmt_exec.swift
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@@ -8,9 +8,9 @@
// Required for experimental features
// REQUIRES: asserts
func testDefer(_ x: Bool) -> Int {
func testDeferIf(_ x: Bool) -> Int {
defer {
print("defer fn")
print("defer testDeferIf")
}
let x = if x {
defer {
@@ -24,9 +24,55 @@ func testDefer(_ x: Bool) -> Int {
print("after if")
return x
}
_ = testDefer(true)
_ = testDeferIf(true)
// CHECK: enter if
// CHECK-NEXT: defer if
// CHECK-NEXT: after if
// CHECK-NEXT: defer fn
// CHECK-NEXT: defer testDeferIf
func testDeferSwitch(_ x: Bool) -> Int {
defer {
print("defer testDeferSwitch")
}
let x = switch x {
case true:
defer {
print("defer case true")
}
print("enter case true")
fallthrough
case false:
defer {
print("defer case false")
}
print("enter case false")
then 1
}
print("after switch")
return x
}
_ = testDeferSwitch(true)
// CHECK: enter case true
// CHECK-NEXT: defer case true
// CHECK-NEXT: enter case false
// CHECK-NEXT: defer case false
// CHECK-NEXT: after switch
// CHECK-NEXT: defer testDeferSwitch
func testFallthrough(_ x: Bool) -> Int {
var z = 0
let y: Int
let x = switch x {
case true:
z = 1
fallthrough
case false:
y = 2
then 3
}
return x + y + z
}
print("fallthrough: \(testFallthrough(true))")
// CHECK: fallthrough: 6