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[Syntax] Allow UnknownSyntax to have children

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This will make it easier to incrementally implement syntax nodes,
while allowing us to embed nodes that we do know about inside ones
that we don't.

https://bugs.swift.org/browse/SR-4062
This commit is contained in:
David Farler
2017-02-27 15:35:48 -08:00
parent 8cf99954e3
commit c958cd65eb
22 changed files with 444 additions and 81 deletions
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12
include/swift/Syntax/ExprSyntax.h
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@@ -23,6 +23,7 @@
#include "swift/Syntax/Syntax.h"
#include "swift/Syntax/SyntaxData.h"
#include "swift/Syntax/TokenSyntax.h"
#include "swift/Syntax/UnknownSyntax.h"
using llvm::Optional;
@@ -61,7 +62,7 @@ public:
#pragma mark - unknown-expression Data
class UnknownExprSyntaxData : public ExprSyntaxData {
class UnknownExprSyntaxData : public UnknownSyntaxData {
UnknownExprSyntaxData(RC<RawSyntax> Raw, const SyntaxData *Parent = nullptr,
CursorIndex IndexInParent = 0);
public:
@@ -76,17 +77,17 @@ public:
#pragma mark - unknown-expression API
class UnknownExprSyntax : public ExprSyntax {
class UnknownExprSyntax : public UnknownSyntax {
friend class SyntaxData;
friend class UnknownExprSyntaxData;
friend class LegacyASTTransformer;
using DataType = UnknownExprSyntaxData;
public:
UnknownExprSyntax(const RC<SyntaxData> Root,
const UnknownExprSyntaxData *Data);
public:
static bool classof(const Syntax *S) {
return S->getKind() == SyntaxKind::UnknownExpr;
}
@@ -333,13 +334,14 @@ public:
/// function-call-argument-list -> function-call-argument
/// function-call-argument-list?
class FunctionCallArgumentListSyntax : public Syntax {
using DataType = FunctionCallArgumentListSyntaxData;
friend struct SyntaxFactory;
friend class FunctionCallArgumentListSyntaxData;
friend class FunctionCallExprSyntax;
friend class Syntax;
friend class SyntaxData;
using DataType = FunctionCallArgumentListSyntaxData;
FunctionCallArgumentListSyntax(const RC<SyntaxData> Root,
const DataType *Data);
@@ -356,7 +358,7 @@ public:
withAdditionalArgument(FunctionCallArgumentSyntax AdditionalArgument) const;
static bool classof(const Syntax *S) {
return S->getKind() == SyntaxKind::FunctionCallExpr;
return S->getKind() == SyntaxKind::FunctionCallArgumentList;
}
};