//===--- CollectionAlgorithms.swift ---------------------------------------===// // // This source file is part of the Swift.org open source project // // Copyright (c) 2014 - 2020 Apple Inc. and the Swift project authors // Licensed under Apache License v2.0 with Runtime Library Exception // // See https://swift.org/LICENSE.txt for license information // See https://swift.org/CONTRIBUTORS.txt for the list of Swift project authors // //===----------------------------------------------------------------------===// //===----------------------------------------------------------------------===// // last //===----------------------------------------------------------------------===// extension BidirectionalCollection { /// The last element of the collection. /// /// If the collection is empty, the value of this property is `nil`. /// /// let numbers = [10, 20, 30, 40, 50] /// if let lastNumber = numbers.last { /// print(lastNumber) /// } /// // Prints "50" /// /// - Complexity: O(1) @inlinable public var last: Element? { return isEmpty ? nil : self[index(before: endIndex)] } } //===----------------------------------------------------------------------===// // firstIndex(of:)/firstIndex(where:) //===----------------------------------------------------------------------===// extension Collection where Element: Equatable { /// Returns the first index where the specified value appears in the /// collection. /// /// After using `firstIndex(of:)` to find the position of a particular element /// in a collection, you can use it to access the element by subscripting. /// This example shows how you can modify one of the names in an array of /// students. /// /// var students = ["Ben", "Ivy", "Jordell", "Maxime"] /// if let i = students.firstIndex(of: "Maxime") { /// students[i] = "Max" /// } /// print(students) /// // Prints "["Ben", "Ivy", "Jordell", "Max"]" /// /// - Parameter element: An element to search for in the collection. /// - Returns: The first index where `element` is found. If `element` is not /// found in the collection, returns `nil`. /// /// - Complexity: O(*n*), where *n* is the length of the collection. @inlinable public func firstIndex(of element: Element) -> Index? { if let result = _customIndexOfEquatableElement(element) { return result } var i = self.startIndex while i != self.endIndex { if self[i] == element { return i } self.formIndex(after: &i) } return nil } } extension Collection { /// Returns the first index in which an element of the collection satisfies /// the given predicate. /// /// You can use the predicate to find an element of a type that doesn't /// conform to the `Equatable` protocol or to find an element that matches /// particular criteria. Here's an example that finds a student name that /// begins with the letter "A": /// /// let students = ["Kofi", "Abena", "Peter", "Kweku", "Akosua"] /// if let i = students.firstIndex(where: { $0.hasPrefix("A") }) { /// print("\(students[i]) starts with 'A'!") /// } /// // Prints "Abena starts with 'A'!" /// /// - Parameter predicate: A closure that takes an element as its argument /// and returns a Boolean value that indicates whether the passed element /// represents a match. /// - Returns: The index of the first element for which `predicate` returns /// `true`. If no elements in the collection satisfy the given predicate, /// returns `nil`. /// /// - Complexity: O(*n*), where *n* is the length of the collection. @inlinable public func firstIndex( where predicate: (Element) throws -> Bool ) rethrows -> Index? { var i = self.startIndex while i != self.endIndex { if try predicate(self[i]) { return i } self.formIndex(after: &i) } return nil } } //===----------------------------------------------------------------------===// // lastIndex(of:)/lastIndex(where:) //===----------------------------------------------------------------------===// extension BidirectionalCollection { /// Returns the last element of the sequence that satisfies the given /// predicate. /// /// This example uses the `last(where:)` method to find the last /// negative number in an array of integers: /// /// let numbers = [3, 7, 4, -2, 9, -6, 10, 1] /// if let lastNegative = numbers.last(where: { $0 < 0 }) { /// print("The last negative number is \(lastNegative).") /// } /// // Prints "The last negative number is -6." /// /// - Parameter predicate: A closure that takes an element of the sequence as /// its argument and returns a Boolean value indicating whether the /// element is a match. /// - Returns: The last element of the sequence that satisfies `predicate`, /// or `nil` if there is no element that satisfies `predicate`. /// /// - Complexity: O(*n*), where *n* is the length of the collection. @inlinable public func last( where predicate: (Element) throws -> Bool ) rethrows -> Element? { return try lastIndex(where: predicate).map { self[$0] } } /// Returns the index of the last element in the collection that matches the /// given predicate. /// /// You can use the predicate to find an element of a type that doesn't /// conform to the `Equatable` protocol or to find an element that matches /// particular criteria. This example finds the index of the last name that /// begins with the letter *A:* /// /// let students = ["Kofi", "Abena", "Peter", "Kweku", "Akosua"] /// if let i = students.lastIndex(where: { $0.hasPrefix("A") }) { /// print("\(students[i]) starts with 'A'!") /// } /// // Prints "Akosua starts with 'A'!" /// /// - Parameter predicate: A closure that takes an element as its argument /// and returns a Boolean value that indicates whether the passed element /// represents a match. /// - Returns: The index of the last element in the collection that matches /// `predicate`, or `nil` if no elements match. /// /// - Complexity: O(*n*), where *n* is the length of the collection. @inlinable public func lastIndex( where predicate: (Element) throws -> Bool ) rethrows -> Index? { var i = endIndex while i != startIndex { formIndex(before: &i) if try predicate(self[i]) { return i } } return nil } } extension BidirectionalCollection where Element: Equatable { /// Returns the last index where the specified value appears in the /// collection. /// /// After using `lastIndex(of:)` to find the position of the last instance of /// a particular element in a collection, you can use it to access the /// element by subscripting. This example shows how you can modify one of /// the names in an array of students. /// /// var students = ["Ben", "Ivy", "Jordell", "Ben", "Maxime"] /// if let i = students.lastIndex(of: "Ben") { /// students[i] = "Benjamin" /// } /// print(students) /// // Prints "["Ben", "Ivy", "Jordell", "Benjamin", "Max"]" /// /// - Parameter element: An element to search for in the collection. /// - Returns: The last index where `element` is found. If `element` is not /// found in the collection, this method returns `nil`. /// /// - Complexity: O(*n*), where *n* is the length of the collection. @inlinable public func lastIndex(of element: Element) -> Index? { if let result = _customLastIndexOfEquatableElement(element) { return result } return lastIndex(where: { $0 == element }) } } //===----------------------------------------------------------------------===// // partition(by:) //===----------------------------------------------------------------------===// extension MutableCollection { /// Reorders the elements of the collection such that all the elements /// that match the given predicate are after all the elements that don't /// match. /// /// After partitioning a collection, there is a pivot index `p` where /// no element before `p` satisfies the `belongsInSecondPartition` /// predicate and every element at or after `p` satisfies /// `belongsInSecondPartition`. This operation isn't guaranteed to be /// stable, so the relative ordering of elements within the partitions might /// change. /// /// In the following example, an array of numbers is partitioned by a /// predicate that matches elements greater than 30. /// /// var numbers = [30, 40, 20, 30, 30, 60, 10] /// let p = numbers.partition(by: { $0 > 30 }) /// // p == 5 /// // numbers == [30, 10, 20, 30, 30, 60, 40] /// /// The `numbers` array is now arranged in two partitions. The first /// partition, `numbers[..
Bool ) rethrows -> Index { return try _halfStablePartition(isSuffixElement: belongsInSecondPartition) } /// Moves all elements satisfying `isSuffixElement` into a suffix of the /// collection, returning the start position of the resulting suffix. /// /// - Complexity: O(*n*) where n is the length of the collection. @inlinable internal mutating func _halfStablePartition( isSuffixElement: (Element) throws -> Bool ) rethrows -> Index { guard var i = try firstIndex(where: isSuffixElement) else { return endIndex } var j = index(after: i) while j != endIndex { if try !isSuffixElement(self[j]) { swapAt(i, j); formIndex(after: &i) } formIndex(after: &j) } return i } } extension MutableCollection where Self: BidirectionalCollection { /// Reorders the elements of the collection such that all the elements /// that match the given predicate are after all the elements that don't /// match. /// /// After partitioning a collection, there is a pivot index `p` where /// no element before `p` satisfies the `belongsInSecondPartition` /// predicate and every element at or after `p` satisfies /// `belongsInSecondPartition`. This operation isn't guaranteed to be /// stable, so the relative ordering of elements within the partitions might /// change. /// /// In the following example, an array of numbers is partitioned by a /// predicate that matches elements greater than 30. /// /// var numbers = [30, 40, 20, 30, 30, 60, 10] /// let p = numbers.partition(by: { $0 > 30 }) /// // p == 5 /// // numbers == [30, 10, 20, 30, 30, 60, 40] /// /// The `numbers` array is now arranged in two partitions. The first /// partition, `numbers[..
Bool
) rethrows -> Index {
let maybeOffset = try withContiguousMutableStorageIfAvailable {
(bufferPointer) -> Int in
let unsafeBufferPivot = try bufferPointer._partitionImpl(
by: belongsInSecondPartition)
return unsafeBufferPivot - bufferPointer.startIndex
}
if let offset = maybeOffset {
return index(startIndex, offsetBy: offset)
} else {
return try _partitionImpl(by: belongsInSecondPartition)
}
}
@inlinable
internal mutating func _partitionImpl(
by belongsInSecondPartition: (Element) throws -> Bool
) rethrows -> Index {
var lo = startIndex
var hi = endIndex
while true {
// Invariants at this point:
//
// * `lo <= hi`
// * all elements in `startIndex ..< lo` belong in the first partition
// * all elements in `hi ..< endIndex` belong in the second partition
// Find next element from `lo` that may not be in the right place.
while true {
guard lo < hi else { return lo }
if try belongsInSecondPartition(self[lo]) { break }
formIndex(after: &lo)
}
// Find next element down from `hi` that we can swap `lo` with.
while true {
formIndex(before: &hi)
guard lo < hi else { return lo }
if try !belongsInSecondPartition(self[hi]) { break }
}
swapAt(lo, hi)
formIndex(after: &lo)
}
}
}
//===----------------------------------------------------------------------===//
// _indexedStablePartition / _partitioningIndex
//===----------------------------------------------------------------------===//
extension MutableCollection {
/// Moves all elements at the indices satisfying `belongsInSecondPartition`
/// into a suffix of the collection, preserving their relative order, and
/// returns the start of the resulting suffix.
///
/// - Complexity: O(*n* log *n*) where *n* is the number of elements.
/// - Precondition:
/// `n == distance(from: range.lowerBound, to: range.upperBound)`
internal mutating func _indexedStablePartition(
count n: Int,
range: Range