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12f8b390c1
It is still possible to get the same behavior by providing an explicit
type context, or in a generic code, but otherwise, `String("")!` will
not compile.
66 lines
1.5 KiB
Swift
66 lines
1.5 KiB
Swift
// RUN: rm -rf %t ; mkdir -p %t
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// RUN: %target-build-swift %s -o %t/a.out3 -swift-version 3 && %target-run %t/a.out3
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// RUN: %target-build-swift %s -o %t/a.out4 -swift-version 4 && %target-run %t/a.out4
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import StdlibUnittest
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#if swift(>=4)
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public typealias ExpectedSubstring = Substring
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#else
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public typealias ExpectedSubstring = String
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#endif
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var Tests = TestSuite("SubstringCompatibility")
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Tests.test("Range/Subscript/ExpectedType") {
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var s = "hello world"
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var sub = s[s.startIndex ..< s.endIndex]
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var subsub = sub[s.startIndex ..< s.endIndex]
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expectType(String.self, &s)
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expectType(ExpectedSubstring.self, &sub)
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expectType(ExpectedSubstring.self, &subsub)
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}
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Tests.test("ClosedRange/Subsript/ExpectedType") {
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var s = "hello world"
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let lastIndex = s.index(before:s.endIndex)
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var sub = s[s.startIndex ... lastIndex]
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var subsub = sub[s.startIndex ... lastIndex]
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expectType(String.self, &s)
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expectType(ExpectedSubstring.self, &sub)
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expectType(ExpectedSubstring.self, &subsub)
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}
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Tests.test("String.init(_:String)/default type") {
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var s = String("")
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expectType(String.self, &s)
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}
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Tests.test("LosslessStringConvertible/generic") {
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func f<T : LosslessStringConvertible>(_ x: T.Type) {
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_ = T("")! // unwrapping optional should work in generic context
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}
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f(String.self)
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}
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Tests.test("LosslessStringConvertible/concrete") {
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_ = String("") as String?
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}
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#if swift(>=4)
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#else
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Tests.test("LosslessStringConvertible/force unwrap") {
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// Force unwrap should still work in Swift 3 mode
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_ = String("")!
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}
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#endif
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runAllTests()
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