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Always run explicit `Sendable` checks on public types and suppress warning printing by default instead of using a special compiler argument. Resolves: rdar://162394810
1.1 KiB
1.1 KiB
Explicit Sendable annotations on public type declarations
If a public type doesn't have an explicit Sendable or non-Sendable annotation it is sometimes hard to discern whether that is intentional or not, especially if a type could be Sendable.
Overview
The Swift compiler would emit a warning if a public type has none of the following:
- A conformance to
Sendableprotocol; - An unavailable conformance to
Sendableprotocol; ~Sendableconformance to suppress the inference.
Let's consider a simple public type without any Senable annotations:
public struct S {
let x: Int
}
When compiling with -Wwarning ExplicitSendable the following warning is going to be produced by the Swift compiler:
1 | public struct S {
| |- warning: public struct 'S' does not specify whether it is 'Sendable' or not [#ExplicitSendable]
| |- note: consider making struct 'S' conform to the 'Sendable' protocol
| `- note: make struct 'S' explicitly non-Sendable to suppress this warning
2 | let x: Int
3 | }