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3ed4059a60
This matches send non sendable but importantly also makes it clear that we are talking about something that doesn't conform to the Sendable protocol which is capitalized. rdar://151802975
32 lines
1.7 KiB
Swift
32 lines
1.7 KiB
Swift
// RUN: %target-typecheck-verify-swift -swift-version 6
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protocol P: Sendable {}
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protocol Q: Sendable {}
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struct One<T> { // expected-note {{consider making generic parameter 'T' conform to the 'Sendable' protocol}}
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var t: T // expected-error {{stored property 't' of 'Sendable'-conforming generic struct 'One' has non-Sendable type 'T'}}
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}
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extension One: P where T: P {}
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// expected-error@-1 {{conditional conformance of type 'One<T>' to protocol 'P' does not imply conformance to inherited protocol 'Sendable'}}
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// expected-note@-2 {{did you mean to explicitly state the conformance with relaxed bounds using 'where T: Sendable'?}}
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// expected-note@-3 {{did you mean to explicitly state the conformance with the same bounds using 'where T: P'?}}
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// expected-note@-4 {{did you mean to explicitly state the conformance with different bounds?}}
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struct Both<T> { // expected-note {{consider making generic parameter 'T' conform to the 'Sendable' protocol}}
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var t: T // expected-error {{stored property 't' of 'Sendable'-conforming generic struct 'Both' has non-Sendable type 'T'}}
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}
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extension Both: P where T: P {}
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// expected-error@-1 {{conditional conformance of type 'Both<T>' to protocol 'P' does not imply conformance to inherited protocol 'Sendable'}}
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// expected-note@-2 {{did you mean to explicitly state the conformance with relaxed bounds using 'where T: Sendable'?}}
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// expected-note@-3 {{did you mean to explicitly state the conformance with the same bounds using 'where T: P'?}}
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// expected-note@-4 {{did you mean to explicitly state the conformance with different bounds?}}
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extension Both: Q where T: Q {}
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func takesSendable<T: Sendable>(_: T) {}
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takesSendable(One<Int>(t: 3))
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takesSendable(Both<Int>(t: 3))
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