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The effective access of an overridden declaration is subject to escalation by -enable-testing. When this is flag is enabled, an interface containing an internal-overriding-public declaration will still print `override`. This is because the effective access of the base of the override is formally internal but effectively public. Instead, use the formal access scope of the overridden declaration to compute its access relative to the override. While I'm here, catch the case where the base declaration is `@usableFromInline` and therefore *will* be printed in the interface. We treat these declarations as effectively public for the purpose of printing `override`. Resolves rdar://64969741
25 lines
1.2 KiB
Swift
25 lines
1.2 KiB
Swift
// RUN: %empty-directory(%t)
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// RUN: %target-swift-frontend -typecheck -module-name Foo -emit-module-interface-path %t/Foo.swiftinterface %s
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// RUN: %target-swift-frontend -compile-module-from-interface %t/Foo.swiftinterface -o %t/Foo.swiftmodule
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// RUN: %target-swift-frontend -typecheck -enable-testing -module-name FooWithTesting -emit-module-interface-path %t/FooWithTesting.swiftinterface %s
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// RUN: %target-swift-frontend -compile-module-from-interface %t/FooWithTesting.swiftinterface -o %t/FooWithTesting.swiftmodule
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public class BaseClass {
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init() { }
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var property: Int { return 1 }
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func doSomething() { }
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subscript(index: Int) -> Int { get { return 0 } set(newValue) {} }
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@usableFromInline func doSomethingInline() {}
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@usableFromInline func doSomethingUsableFromInline() {}
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}
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public class DerivedClass: BaseClass {
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public override init() { super.init() }
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public override var property : Int { return 0 }
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public override func doSomething() { }
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public override subscript(index: Int) -> Int { get {return 0} set(newValue) {} }
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@inlinable public override func doSomethingInline() { super.doSomethingInline() }
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@usableFromInline override func doSomethingUsableFromInline() { super.doSomethingUsableFromInline() }
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}
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