Doug Gregor
ad2fa39eaa
Treat deducible generic parameter types as unresolved types, because
...
they need to be substituted away for any type containing them to be
useful. A nice side-effect of this is that we'll actually properly
walk into the source type when a generic function returns, e.g., a
tuple type that involves type parameters not resolved by the input
arguments.
Swift SVN r2302
2012-07-03 23:23:25 +00:00
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