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66e416b604
We might infer internal function labels as `$0` from a closure with which a variable is initialised. But we don’t want to print the function signature as `(_ $0: Int) -> Int` because `$0` is not a valid variable name to declare. So, in the case described above, only print the type. Fixes rdar://77462547
13 lines
450 B
Swift
13 lines
450 B
Swift
// RUN: %empty-directory(%t)
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// RUN: %target-swift-frontend -typecheck %s -emit-module-interface-path %t/main.swiftinterface -enable-library-evolution
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// RUN: %FileCheck %s < %t/main.swiftinterface
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// CHECK: import Swift
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// CHECK: public let MyClosureVar: (Swift.Int) -> Swift.Int
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public let MyClosureVar: (Int) -> Int = { $0 }
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// CHECK: public var MyOtherClosureVar: (_ x: Swift.Int) -> Swift.Int
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public let MyOtherClosureVar: (_ x: Int) -> Int
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