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The result of st_mult() is the same no matter the order of its arguments. It invokes the macro unsigned_mult_overflows(), which divides the second parameter by the first one. Pass constants first to allow that division to be done already at compile time. Signed-off-by: Rene Scharfe <l.s.r@web.de> Reviewed-by: Jeff King <peff@peff.net> Signed-off-by: Junio C Hamano <gitster@pobox.com>
18 KiB
18 KiB