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Oleg Nesterov
0b7747a547
If a single-threaded process exits do_notify_pidfd() will be called twice, from exit_notify() and right after that from do_notify_parent(). 1. Change exit_notify() to call do_notify_pidfd() if the exiting task is not ptraced and it is not a group leader. 2. Change do_notify_parent() to call do_notify_pidfd() unconditionally. If tsk is not ptraced, do_notify_parent() will only be called when it is a group-leader and thread_group_empty() is true. This means that if tsk is ptraced, do_notify_pidfd() will be called from do_notify_parent() even if tsk is a delay_group_leader(). But this case is less common, and apart from the unnecessary __wake_up() is harmless. Granted, this unnecessary __wake_up() can be avoided, but I don't want to do it in this patch because it's just a consequence of another historical oddity: we notify the tracer even if !thread_group_empty(), but do_wait() from debugger can't work until all other threads exit. With or without this patch we should either eliminate do_notify_parent() in this case, or change do_wait(WEXITED) to untrace the ptraced delay_group_leader() at least when ptrace_reparented(). Signed-off-by: Oleg Nesterov <oleg@redhat.com> Link: https://lore.kernel.org/r/20250323171955.GA834@redhat.com Signed-off-by: Christian Brauner <brauner@kernel.org>
Linux kernel
============
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