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35d5b68722
Using as a sub expression in default argument still allowed as expression macros behave the same as built-in magic literals
33 lines
972 B
Swift
33 lines
972 B
Swift
// REQUIRES: swift_swift_parser
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// RUN: %empty-directory(%t)
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// RUN: %host-build-swift -swift-version 5 -emit-library -o %t/%target-library-name(MacroDefinition) -module-name=MacroDefinition %S/Inputs/syntax_macro_definitions.swift -g -no-toolchain-stdlib-rpath
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// RUN: %target-typecheck-verify-swift -swift-version 5 -load-plugin-library %t/%target-library-name(MacroDefinition) %s
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@freestanding(expression)
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macro MagicLine() -> Int = #externalMacro(module: "MacroDefinition", type: "MagicLineMacro")
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struct LineContainer {
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let line: Int
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}
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func partOfDefaultArgumentOkay(container: LineContainer = .init(line: #MagicLine)) {
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print(container.line)
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}
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func parenthesizedExpansionAtDeclOkay(line: Int = (#MagicLine)) {
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print(line)
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}
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func builtInOkay(line: Int = #line) {
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print(line)
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}
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// expected-error@+1{{non-built-in macro cannot be used as default argument}}
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func asDefaultArgument(line: Int = #MagicLine) {
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print(line)
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}
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asDefaultArgument()
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